feature: solution for AB503

2026-09-27 22:01:03 +02:00
parent e265cc4c4a
commit 340bcaf31b
1 changed files with 1 additions and 1 deletions
@@ -17,4 +17,4 @@ Die Formeln ineinander einsetzen:
 $\rightarrow W = \frac{U^2}{R} \cdot t $

 Nun die gegebenen Werte einsetzen:  
-$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}$
+$\rightarrow W = \frac{\left(\qty{10}{\volt}\right)^2}{\qty{100}{\ohm}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt^2}}{\qty{100}{\volt/\ampere}} \cdot\qty{1}{\hour}= \frac{\qty{100}{\volt\ampere\hour}}{100} = \qty{1}{\watt}$