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50ohm-contents-dl/contents/slides/brolikriktare.md
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SuperminarenandClaude Sonnet 5.5 f7fa8cfbc1 Swedish adaptation: Instegscertifikat and HAREC content
- Sections and slides rewritten in Swedish; German law and institutions replaced by
  Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified
  statements marked "% TODO VERIFY"
- New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv)
- Exam-question tags, BNetzA question pool, solutions and the German SWL course removed
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  upstream: it references a missing photo)
- Changed from the original: not endorsed by DARC e.V., SSA or PTS

Co-Authored-By: Claude Sonnet 5.5 <[email protected]>
2026-10-10 15:03:03 +02:00

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<left>
[picture:965:a_brueckenlgeichrichter:Brolikriktare]
</left>
<right>
* Utökad och vanlig likriktarkoppling
* Båda halvperioderna utnyttjas
* Pulserande likspänning på utgången med dubbla frekvensen mot ingångsspänningen
</right>
--- style="font-size: smaller;"
[include:applet_gleichrichter_2]
---
### Filtrering
<left>
[picture:66:a_netzteil_Ucs:Likriktarkoppling med filtrering]
</left>
<right>
* Med laddningskondensator $C_L$ och LC-filter med $C_S$
* Mindre amplituder på den pulserande likspänningen
* Kondensatorerna laddas upp till sekundärsidans topspänning
</right>
<note>
</note>
---
#### Lösningsgång
* givet: $U_P = \qty{230}{\volt}$
* givet: $ü = 8:1$
* givet: $U_D = \qty{0,6}{\volt}$
* sökt: $\hat{U}$
<fragment>
$ü = \frac{U_P}{U_S} \Rightarrow U_S = \frac{U_P}{ü} = \frac{\qty{230}{\volt}}{8} = \qty{28,75}{\volt}$
</fragment>
<fragment>
I tomgång kan diodspänningen försummas.
$\hat{U} = U_S \cdot \sqrt{2} = \qty{28,75}{\volt} \cdot 1,41 \approx \qty{40}{\volt}$
</fragment>