SuperminarenandClaude Sonnet 5.5
f7fa8cfbc1
- Sections and slides rewritten in Swedish; German law and institutions replaced by Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified statements marked "% TODO VERIFY" - New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv) - Exam-question tags, BNetzA question pool, solutions and the German SWL course removed - Static pages, snippets, applets, READMEs and image alt-texts translated - TikZ labels translated; SVG drawings regenerated (drawing 689 still fails to build upstream: it references a missing photo) - Changed from the original: not endorsed by DARC e.V., SSA or PTS Co-Authored-By: Claude Sonnet 5.5 <[email protected]>
66 lines
2.1 KiB
Markdown
66 lines
2.1 KiB
Markdown
### Parallellsvängningskrets
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* Spolar och kondensatorer kombineras
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* Tänk också på *lindningskapacitansen*
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* Därigenom kommer ”osynliga” kapacitanser med i kopplingen
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<note>
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Spolens egenkapacitans
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</note>
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---
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#### Lösningsgång
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* givet: $C_1 = \qty{0,10}{\nano\farad}$
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* givet: $C_2 = \qty{47}{\pico\farad}$
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* givet: $C_3 = \qty{22}{\pico\farad}$
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* sökt: $C_{\mathrm{tot}}$
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<fragment>
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$\begin{split} \tfrac{1}{C_{\mathrm{tot}}} &= \tfrac{1}{C_1} + \tfrac{1}{C_2} + \tfrac{1}{C_3} = \tfrac{1}{\qty{0,10}{\nano\farad}} + \tfrac{1}{\qty{47}{\pico\farad}} + \tfrac{1}{\qty{22}{\pico\farad}}\\ &= \qty{7,67e10}{\farad^{-1}}\\ \Rightarrow C_{\mathrm{tot}} &= \frac{1}{\qty{7,67e10}{\farad^{-1}}} \approx \qty{13,0}{\pico\farad} \end{split}$
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</fragment>
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---
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#### Lösningsgång
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* givet: $C_1 = \qty{0,1}{\nano\farad}$
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* givet: $C_2 = \qty{1,5}{\nano\farad}$
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* givet: $C_3 = \qty{220}{\pico\farad}$
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* givet: $C_L = \qty{1}{\pico\farad}$
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* sökt: $C_{\mathrm{tot}}$
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<fragment>
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$\begin{split} C_{\mathrm{tot}} &= C_1 + C_2 + C_3 + C_L\\ &= \qty{0,1}{\nano\farad} + \qty{1,5}{\nano\farad} + \qty{220}{\pico\farad} + \qty{1}{\pico\farad}\\ &= \qty{1821}{\pico\farad} \end{split}$
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</fragment>
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<note>
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Tänk på enhetsprefixen
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</note>
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---
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#### Lösningsgång
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* givet: $R = \qty{100}{\ohm}$
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* givet: $L = \qty{100}{\micro\henry}$
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* givet: $f = \qty{1}{\mega\hertz}$
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* sökt: $Z$
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<fragment>
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$\begin{split} X_L &= \omega \cdot L = 2\pi \cdot f \cdot L\\ &= 2\pi \cdot \qty{1}{\mega\hertz} \cdot \qty{100}{\micro\henry} = \qty{628}{\ohm}\end{split}$
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</fragment>
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<fragment>
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$Z = \sqrt{R^2 + X^2} = \sqrt{(\qty{100}{\ohm})^2 + (\qty{628}{\ohm})^2} \approx \qty{636}{\ohm}$
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</fragment>
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---
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#### Lösningsgång
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* givet: $R = \qty{100}{\ohm}$
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* givet: $C = \qty{100}{\nano\farad}$
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* givet: $f = \qty{1}{\mega\hertz}$
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* sökt: $Z$
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<fragment>
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$\begin{split} X_C &= \frac{1}{\omega \cdot C} = \frac{1}{2\pi \cdot f \cdot C}\\ &= \frac{1}{2\pi \cdot \qty{1}{\mega\hertz} \cdot \qty{100}{\nano\farad}} = \qty{159}{\ohm}\end{split}$
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</fragment>
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<fragment>
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$Z = \sqrt{R^2 + X^2} = \sqrt{(\qty{100}{\ohm})^2 + (\qty{159}{\ohm})^2} \approx \qty{188}{\ohm}$
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</fragment>
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