fix, slides: get rid of \nonumber commands
We do not need the equation environment. It introduces the equation numbering, which we then disable by `\nonumber`. We just need the split-environment.
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@@ -67,7 +67,7 @@ Etwa 99% der Sendeleistung befinden sich in der Bandbreite
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* gesucht: $B$
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<fragment>
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$\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ &= 2 \cdot (1,8kHz + 2kHz) = 7,6kHz \end{split}\end{equation}$
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$\begin{split} B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ &= 2 \cdot (1,8kHz + 2kHz) = 7,6kHz \end{split}$
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</fragment>
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---
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[question:AE308]
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@@ -78,7 +78,7 @@ $\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}
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* gesucht: $B$
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<fragment>
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$\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ &= 2 \cdot (2,5kHz + 2,7kHz) = 10,4kHz \end{split}\end{equation}$
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$\begin{split} B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ &= 2 \cdot (2,5kHz + 2,7kHz) = 10,4kHz \end{split}$
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</fragment>
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---
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[question:AE311]
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@@ -89,7 +89,7 @@ $\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}
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* gesucht: $f_{\textrm{mod max}}$
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<fragment>
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$\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ \Rightarrow f_{mod max} &= \frac{B}{2} - \Delta f_T\\ &= \frac{10kHz}{2} - 2,5kHz = 2,5kHz \end{split}\end{equation}$
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$\begin{split} B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ \Rightarrow f_{mod max} &= \frac{B}{2} - \Delta f_T\\ &= \frac{10kHz}{2} - 2,5kHz = 2,5kHz \end{split}$
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</fragment>
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---
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[question:AE312]
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@@ -100,7 +100,7 @@ $\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}
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* gesucht: $\Delta f_{\textrm{T}}$
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<fragment>
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$\begin{equation}\begin{split}\nonumber B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ \Rightarrow \Delta f_T &= \frac{B}{2} - f_{mod max}\\ &= \frac{10kHz}{2} - 2,7kHz = 2,3kHz \end{split}\end{equation}$
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$\begin{split} B &\approx 2 \cdot (\Delta f_{\textrm{T}} + f_{\textrm{mod max}})\\ \Rightarrow \Delta f_T &= \frac{B}{2} - f_{mod max}\\ &= \frac{10kHz}{2} - 2,7kHz = 2,3kHz \end{split}$
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</fragment>
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---
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[question:AE310]
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