Superminaren/50ohm-contents-dl
1
0
Fork 0
Code Issues Pull Requests Actions Packages Projects Releases Wiki Activity

AK105.md angepasst qty

Browse Source
This commit is contained in:
Ralf Mahler
2026-06-16 20:59:00 +02:00
parent 38337dd117
commit eb00d095f8
1 changed files with 1 additions and 1 deletions
Download Patch File Download Diff File Expand all files Collapse all files
contents/solutions/AK105.md
+1 -1
View File
@@ -16,7 +16,7 @@ $d = \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E}$
## Einsetzen
$d_{{40}^\circ} = \frac{\sqrt{\qty{30}{\ohm} \cdot P_{{40}^\circ}}}{E} = \frac{\sqrt{\qty{30}{\ohm} \cdot 0,25 \cdot P_\mathrm{EIRP}}}{E} = \frac{\sqrt{0,25} \cdot \sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = \sqrt{0,25} \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot d$
$d_{\qty{40}{^\circ}} = \frac{\sqrt{\qty{30}{\ohm} \cdot P_{\qty{40}{^\circ}}}}{E} = \frac{\sqrt{\qty{30}{\ohm} \cdot 0,25 \cdot P_\mathrm{EIRP}}}{E} = \frac{\sqrt{0,25} \cdot \sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = \sqrt{0,25} \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot \frac{\sqrt{\qty{30}{\ohm} \cdot P_\mathrm{EIRP}}}{E} = 0,5 \cdot d$
## Interpretation der Formel