fix: bridge circuit equation
For U_AB, the reference voltage U_A has to be subtracted from the target voltage U_B. It is not necessary to use absolute value bars. Thanks-To: [email protected]
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@@ -32,5 +32,5 @@ $\frac{U_A}{U} = \frac{R_1}{R_1 + R_2} \Rightarrow U_A = \frac{R_1}{R_1 + R_2} \
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$\frac{U_B}{U} = \frac{R_3}{R_3 + R_4} \Rightarrow U_B = \frac{R_3}{R_3 + R_4} \cdot U = \frac{\qty{10}{\kilo\ohm}}{\qty{10}{\kilo\ohm} + \qty{1}{\kilo\ohm}} \cdot \qty{11}{\volt} = \qty{10}{\volt}$
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</fragment>
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<fragment>
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$U_{AB} = |U_A - U_B| = |\qty{1}{\volt} - \qty{10}{\volt}| = \qty{9}{\volt}$
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</fragment>
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$U_{AB} = U_B - U_A = \qty{10}{\volt} - \qty{1}{\volt} = \qty{9}{\volt}$
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</fragment>
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