fix: use R_1 \parallel R_2 instead of R_{1 \parallel 2}

It is more consistent to series connections, where `R_1 + R_2` used
instead of `R_{1 + 2}`.
This commit is contained in:
Mario Haustein
2026-02-22 17:56:49 +01:00
parent 826d1f0f47
commit 4d49ee4e39
@@ -35,7 +35,7 @@ $U = R_{\mathrm{ges}} \cdot I = \qty{15}{\kilo\ohm} \cdot \qty{2}{\milli\ampere}
$R_{\mathrm{ges}} = R_1 + \frac{R_1 \cdot R_2}{R_1 + R_2} = \qty{10}{\kilo\ohm} + \frac{\qty{10}{\kilo\ohm} \cdot \qty{10}{\kilo\ohm}}{\qty{10}{\kilo\ohm} + \qty{10}{\kilo\ohm}} = \qty{15}{\kilo\ohm}$
</fragment>
<fragment>
$\frac{U_3}{U} = \frac{R_{2\parallel 3}}{R_{\mathrm{ges}}} \Rightarrow U_3 = \frac{R_{2\parallel 3}}{R_{\mathrm{ges}}} \cdot U = \frac{\qty{5}{\kilo\ohm}}{\qty{15}{\kilo\ohm}} \cdot \qty{15}{\volt} = \qty{5}{\volt}$
$\frac{U_3}{U} = \frac{R_2 \parallel R_3}{R_{\mathrm{ges}}} \Rightarrow U_3 = \frac{R_2 \parallel R_3}{R_{\mathrm{ges}}} \cdot U = \frac{\qty{5}{\kilo\ohm}}{\qty{15}{\kilo\ohm}} \cdot \qty{15}{\volt} = \qty{5}{\volt}$
</fragment>
<fragment>
$I_3 = \frac{U_3}{R_3} = \frac{\qty{5}{\volt}}{\qty{10}{\kilo\ohm}} = \qty{0,5}{\milli\ampere}$
@@ -49,7 +49,7 @@ $I_3 = \frac{U_3}{R_3} = \frac{\qty{5}{\volt}}{\qty{10}{\kilo\ohm}} = \qty{0,5}{
* gesucht: $P_2$
<fragment>
$\frac{U_2}{U} = \frac{R_{2\parallel 3}}{R_{\mathrm{ges}}} \Rightarrow U_2 = \frac{R_{2\parallel 3}}{R_{\mathrm{ges}}} \cdot U = \frac{\qty{5}{\kilo\ohm}}{\qty{15}{\kilo\ohm}} \cdot \qty{15}{\volt} = \qty{5}{\volt}$
$\frac{U_2}{U} = \frac{R_2 \parallel R_3}{R_{\mathrm{ges}}} \Rightarrow U_2 = \frac{R_2 \parallel R_3}{R_{\mathrm{ges}}} \cdot U = \frac{\qty{5}{\kilo\ohm}}{\qty{15}{\kilo\ohm}} \cdot \qty{15}{\volt} = \qty{5}{\volt}$
</fragment>
<fragment>
$P_2 = \frac{U_2^2}{R_2} = \frac{(\qty{5}{\volt})^2}{\qty{10}{\kilo\ohm}} = \qty{2,5}{\milli\watt}$
@@ -104,10 +104,10 @@ $\begin{split} R_{\mathrm{ges}} &= \frac{(R_1 + R_2) \cdot (R_3 + R_4)}{(R_1 + R
</right>
<fragment>
$\frac{U_2}{U_B} = \frac{R_{2\parallel L}}{R_{\mathrm{ges}}}$
$R_{2\parallel L} = \frac{R_2 \cdot R_L}{R_2 + R_L} = \frac{\qty{2,2}{\kilo\ohm} \cdot \qty{8,2}{\kilo\ohm}}{\qty{2,2}{\kilo\ohm} + \qty{8,2}{\kilo\ohm}} = \qty{1,74}{\kilo\ohm}$
$R_{\mathrm{ges}} = R_1 + R_{2\parallel L} = \qty{10}{\kilo\ohm} + \qty{1,74}{\kilo\ohm} = \qty{11,74}{\kilo\ohm}$
$\frac{U_2}{U_B} = \frac{R_2 \parallel R_L}{R_{\mathrm{ges}}}$
$R_2 \parallel R_L = \frac{R_2 \cdot R_L}{R_2 + R_L} = \frac{\qty{2,2}{\kilo\ohm} \cdot \qty{8,2}{\kilo\ohm}}{\qty{2,2}{\kilo\ohm} + \qty{8,2}{\kilo\ohm}} = \qty{1,74}{\kilo\ohm}$
$R_{\mathrm{ges}} = R_1 + R_2 \parallel R_L = \qty{10}{\kilo\ohm} + \qty{1,74}{\kilo\ohm} = \qty{11,74}{\kilo\ohm}$
</fragment>
<fragment>
$U_2 = \frac{R_{2\parallel L}}{R_{\mathrm{ges}}} \cdot U_B = \frac{\qty{1,74}{\kilo\ohm}}{\qty{11,74}{\kilo\ohm}} \cdot \qty{12}{\volt} \approx \qty{1,8}{\volt}$
$U_2 = \frac{R_2 \parallel R_L}{R_{\mathrm{ges}}} \cdot U_B = \frac{\qty{1,74}{\kilo\ohm}}{\qty{11,74}{\kilo\ohm}} \cdot \qty{12}{\volt} \approx \qty{1,8}{\volt}$
</fragment>