50ohm-contents-dl/contents/slides/brolikriktare.md at sv

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SuperminarenandClaude Sonnet 5.5 f7fa8cfbc1 Swedish adaptation: Instegscertifikat and HAREC content

- Sections and slides rewritten in Swedish; German law and institutions replaced by
  Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified
  statements marked "% TODO VERIFY"
- New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv)
- Exam-question tags, BNetzA question pool, solutions and the German SWL course removed
- Static pages, snippets, applets, READMEs and image alt-texts translated
- TikZ labels translated; SVG drawings regenerated (drawing 689 still fails to build
  upstream: it references a missing photo)
- Changed from the original: not endorsed by DARC e.V., SSA or PTS

Co-Authored-By: Claude Sonnet 5.5 <[email protected]>

2026-10-10 15:03:03 +02:00

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[picture:965:a_brueckenlgeichrichter:Brolikriktare] * Utökad och vanlig likriktarkoppling * Båda halvperioderna utnyttjas * Pulserande likspänning på utgången med dubbla frekvensen mot ingångsspänningen --- style="font-size: smaller;" [include:applet_gleichrichter_2]

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[picture:66:a_netzteil_Ucs:Likriktarkoppling med filtrering] * Med laddningskondensator $C_L$ och LC-filter med $C_S$ * Mindre amplituder på den pulserande likspänningen * Kondensatorerna laddas upp till sekundärsidans topspänning --- #### Lösningsgång * givet: $U_P = \qty{230}{\volt}$ * givet: $ü = 8:1$ * givet: $U_D = \qty{0,6}{\volt}$ * sökt: $\hat{U}$ $ü = \frac{U_P}{U_S} \Rightarrow U_S = \frac{U_P}{ü} = \frac{\qty{230}{\volt}}{8} = \qty{28,75}{\volt}$ I tomgång kan diodspänningen försummas. $\hat{U} = U_S \cdot \sqrt{2} = \qty{28,75}{\volt} \cdot 1,41 \approx \qty{40}{\volt}$

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