50ohm-contents-dl/contents/slides/brokoppling.md at sv

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SuperminarenandClaude Sonnet 5.5 f7fa8cfbc1 Swedish adaptation: Instegscertifikat and HAREC content

- Sections and slides rewritten in Swedish; German law and institutions replaced by
  Swedish/CEPT/ITU equivalents (PTS, SSA, PTSFS 2025:1, SSMFS 2008:18), unverified
  statements marked "% TODO VERIFY"
- New toc: INSTEG, HAREC, UPPGRADERING; section idents are Swedish (see ident-map.tsv)
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- Changed from the original: not endorsed by DARC e.V., SSA or PTS

Co-Authored-By: Claude Sonnet 5.5 <[email protected]>

2026-10-10 15:03:03 +02:00

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[picture:343:a_Brückenschaltung:Typisk brokoppling med 4 motstånd]

\frac{R_1}{R_2} = \frac{R_3}{R_4}

Koppling av 4 motstånd för resistansmätning
Två parallellkopplade spänningsdelare
Vid lika stora delningsförhållanden flyter ingen ström över bron Wheatstonebrygga

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Lösningsgång

givet: R_1 = R_4 = \qty{1}{\kilo\ohm}
givet: R_2 = R_3 = \qty{10}{\kilo\ohm}
givet: U = \qty{11}{\volt}
sökt: U_{AB}

$\frac{U_A}{U} = \frac{R_1}{R_1 + R_2} \Rightarrow U_A = \frac{R_1}{R_1 + R_2} \cdot U = \frac{\qty{1}{\kilo\ohm}}{\qty{1}{\kilo\ohm} + \qty{10}{\kilo\ohm}} \cdot \qty{11}{\volt} = \qty{1}{\volt}$ $\frac{U_B}{U} = \frac{R_3}{R_3 + R_4} \Rightarrow U_B = \frac{R_3}{R_3 + R_4} \cdot U = \frac{\qty{10}{\kilo\ohm}}{\qty{10}{\kilo\ohm} + \qty{1}{\kilo\ohm}} \cdot \qty{11}{\volt} = \qty{10}{\volt}$ $U_{AB} = U_B - U_A = \qty{10}{\volt} - \qty{1}{\volt} = \qty{9}{\volt}$

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Lösningsgång

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